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Use the discriminant to determine the number of real solutions to the quadratic equation.

6a2−11a+9=0
What is the number of real solutions?
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User Durwin
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1 Answer

3 votes

Answer:

0

Explanation:

Use discramnt formula


b {}^(2) - 4ac

Where 6 is a, 11 is b and 9 is c


11 {}^(2) - 4(6)(9)


121 - 216 = - 95

Since the discramnt is negative, there are no real solutions and it will only produce imaginary solutions

User Spozun
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