Question

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Subtract 3x—y—z from the sum of 3x—y + z and 2x–y —z. what is the the

coefficient of x in the result?
with step pls​

Answer 1

the coefficient of x is 2

Explanation:

(3x - y + z) + (2x - y - z) - (3x - y - z) = 3x - y + z + 2x - y - z - (3x - y - z)

Apply the distributive law: - (a - b) = -a + b

Therefore, - (3x - y - z) = -3x + y + z

So (3x - y + z) + (2x - y - z) - (3x - y - z) = 3x - y + z + 2x - y - z - 3x + y + z

Collect like terms: = 3x + 2x - 3x - y - y + y + z - z + z

Combine like terms: = 2x - y + z

Therefore, the coefficient of x is 2

Therefore, the coefficient of x is 2