Question

What is the half-life for the decomposition of NOCl when the concentration of NOCl is 0.15 M?

a) 8.63 × 10⁶ s
b) 1.07 × 10⁷ s
c) 5.39 × 10⁶ s
d) 2.68 × 10⁶ s

Answer 1

The half-life for the decomposition of NOCl when the concentration of NOCl is 0.15 M is approximately 8.33 x 10^7 seconds.

Step-by-step explanation:

The half-life for the decomposition of NOCl can be determined using the rate constant for the second-order reaction and the initial concentration of NOCl. The rate constant given is 8.0 x 10-8 L mol-1 s-1 and the initial concentration of NOCl is 0.15 M. To find the half-life, you can use the formula:

t1/2 = 1 / (k * [NOCl])

Substituting the given values:

t1/2 = 1 / (8.0 x 10-8 L mol-1 s-1 * 0.15 M)

Simplifying the expression:

t1/2 = 1 / 1.2 x 10-8 mol L-1 s-1

t1/2 = 8.33 x 107 s

Therefore, the half-life for the decomposition of NOCl when the concentration of NOCl is 0.15 M is approximately 8.33 x 107 seconds.