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Write the balanced chemical equations for the following reactions

(a) Sodium carbonate on reaction with hydrochloric acid in equal molar concentrations gives sodium chloride and sodium hydrogencarbonate.
(b) Sodium hydrogencarbonate on reaction with hydrochloric acid gives sodium chloride, water and liberates carbon dioxide.
(c) Copper sulphate on treatment with potassium iodide precipitates cuprous iodide (Cu₂I₂), liberates iodine gas and also forms potassium sulphate.

1 Answer

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Final answer:

The balanced chemical equations for the given reactions are: (a) Na2CO3 (aq) + 2HCl(aq) -> 2NaCl(aq) + NaHCO3 (aq), (b) NaHCO3 (aq) + HCl(aq) -> NaCl(aq) + H2O(l) + CO2 (g), (c) CuSO4 (aq) + 4KI(aq) -> Cu2I2 (s) + I2 (g) + 2K2SO4 (aq).

Step-by-step explanation:

For the given reactions:

(a) Sodium carbonate on reaction with hydrochloric acid in equal molar concentrations gives sodium chloride and sodium hydrogencarbonate. The balanced chemical equation for this reaction is:

Na2CO3 (aq) + 2HCl(aq) → 2NaCl(aq) + NaHCO3 (aq)

(b) Sodium hydrogencarbonate on reaction with hydrochloric acid gives sodium chloride, water and liberates carbon dioxide. The balanced chemical equation for this reaction is:

NaHCO3 (aq) + HCl(aq) → NaCl(aq) + H2O(l) + CO2 (g)

(c) Copper sulphate on treatment with potassium iodide precipitates cuprous iodide (Cu2I2), liberates iodine gas, and also forms potassium sulphate. The balanced chemical equation for this reaction is:

CuSO4 (aq) + 4KI(aq) → Cu2I2 (s) + I2 (g) + 2K2SO4 (aq)

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