Final answer:
The average fluid velocity in a 3.00 cm diameter pipe, given a 0.500 T magnetic field and a 60.0 mV Hall voltage, is 2.0 m/s.
Step-by-step explanation:
The average fluid velocity in a pipe can be calculated using the equation:
v = (2 * E * V) / (B * d)
Where v is the average fluid velocity, E is the electric field or Hall voltage, V is the Hall voltage, B is the applied magnetic field, and d is the diameter of the pipe.
Plugging in the given values, we get:
v = (2 * 60.0 mV * 0.500 T) / (0.0300 m)
Simplifying the equation gives the average fluid velocity v = 2.0 m/s. Therefore, the correct answer is option b) 2.0 m/s