Final answer:
The bond order can be determined by counting the number of bonding and antibonding electrons. The electron configuration provided has 6 bonding electrons and 0 antibonding electrons, resulting in a bond order of 3.
Step-by-step explanation:
The bond order can be determined by subtracting the number of antibonding electrons from the number of bonding electrons and dividing by 2. The electron configuration given in the question is (σ2s)₂(σ2s)₂(σ2px)₂(π2py,π2pz)₄(π2py,π*2pz)₃. To calculate the bond order, we count the number of bonding and antibonding electrons.
The number of bonding electrons is 6 ((σ2s)₂(σ2s)₂(σ2px)₂).
The number of antibonding electrons is 0 ((π2py,π*2pz)₃).
Therefore, the bond order is (6 - 0) ÷ 2 = 3. So, the correct answer is option c) 3.