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Repeat the preceding problem with 0.500 kg of ice, assuming that the ice is initially in a copper container of mass 1.50 kg in equilibrium with the ice.

a) Final temperature = -0.6°C, Ice melted = 0.20 kg
b) Final temperature = 0.6°C, Ice melted = 0.10 kg
c) Final temperature = 0.0°C, Ice melted = 0.15 kg
d) Final temperature = -1.2°C, Ice melted = 0.30 kg

1 Answer

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Final answer:

The question requires applying principles of thermodynamics to determine the final temperature and quantity of ice melted in a copper container initially in equilibrium with the ice, utilizing specific heat, latent heat, and the law of conservation of energy.

Step-by-step explanation:

The question pertains to the topic of thermodynamics and involves calculating the final temperature and the amount of ice melted when a copper container in equilibrium with ice is subject to a change in temperature.

This requires understanding of concepts such as specific heat capacity, latent heat, and the conservation of energy. Given the details of the ice and copper container, and ignoring any external effects, one would set up a thermal equilibrium equation equating heat lost by the copper container to the heat gained by the ice for melting and raising its temperature.

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