Answer:
6 ; 24 ; 5.4 ; 24.6
Explanation:
Given that:
Number of samples from each high school = 30
Proportion of students from high school A = 20%
Proportion of students from high school B = 18%
Number of sample A ; n(A) = 30
Proportion of sample A ; p(A) = 0.20
Number of sample B ; n(B) = 30
Proportion of sample B ; p(B) = 0.18
1.)
n(A).p(A) = 30 * 0.20 = 6
2.)
n(A). (1 - p(A))
30 * (1 - 0.20)
30 * 0.8 = 24
3.)
n(B).p(B) = 30 * 0.18 = 5.4
4.)
n(B). (1 - p(B))
30 * (1 - 0.18)
30 * 0.82
= 24.6
Shape of sampling distribution is not approximately normal ;
Both nApA and nBpB are < 10