Final answer:
In a double-slit interference experiment, the distance between the slits and the screen is given. The distance on the screen between the central maximum and the third maximum can be found using the formula y = (3λL)/(2d), where y is the distance, λ is the wavelength of light, L is the distance between the screen and the slits, and d is the distance between the slits. The distance between the second and fourth maxima can be found by subtracting the distance between the central maximum and the second maximum from the distance between the central maximum and the fourth maximum.
Step-by-step explanation:
In a double-slit interference experiment, the distance between the slits is given as d = 0.150 mm and the distance between the screen and the slits is given as L = 3.00 m. To find the distance on the screen between the central maximum and the third maximum, we can use the formula:
y = (3λL)/(2d)
where y is the distance between the central maximum and the nth maximum, λ is the wavelength of light, L is the distance between the screen and the slits, and d is the distance between the slits. For the third maximum (n = 3), substituting the given values, we have:
y = (3λL)/(2d) = (3 * λ * 3.00 m)/(2 * 0.150 mm)
Simplifying and converting mm to m, we get:
y = 0.009 * λ m
So, the distance on the screen between the central maximum and the third maximum is 0.009 times the wavelength of light.
To find the distance between the second and fourth maxima, we can subtract the distance between the central maximum and the second maximum from the distance between the central maximum and the fourth maximum. Using the same formula, we have:
y2 = 0.009 * λ m
y4 = 0.016 * λ m
Therefore, the distance between the second and fourth maxima is given by:
y4 - y2 = (0.016 - 0.009) * λ m