Question

An astronaut on Mars kicks a soccer ball at an angle of 45° with an initial velocity of 15 m/s. If the acceleration of gravity on Mars is 3.7m/s2, (a) what is the range of the soccer kick on a flat surface? (b) What would be the range of the same kick on the Moon, where gravity is one-sixth that of Earth?

a) 10.9 m, 65.4 m
b) 32.6 m, 195.6 m
c) 54.3 m, 326.4 m
d) 76.1 m, 456.5 m

Answer 1

The range of the soccer kick on Mars is 10.9 m and on the Moon is 65.4 m.

Step-by-step explanation:

To calculate the range of the soccer kick on Mars, we can use the range formula for projectile motion:

Range = (Velocity² * sin(2*Angle)) / Acceleration due to gravity

Plugging in the given values, we get Range = (15² * sin(2*45)) / 3.7 = 10.9 m.

To calculate the range of the same kick on the Moon, we need to use the acceleration due to gravity on the Moon, which is one-sixth that of Earth.

Therefore, the range would be (15² * sin(2*45)) / (9.8/6) = 65.4 m.