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A force is applied to a block to move it up a 30° incline. The incline is frictionless. If F=65.0N and M=5.00kg, what is the magnitude of the acceleration of the block?

a) 10.9 m/s²
b) 8.2 m/s²
c) 6.5 m/s²
d) 4.9 m/s²

1 Answer

4 votes

Final answer:

The magnitude of the acceleration of the block is 1.33 m/s².

Step-by-step explanation:

The magnitude of the acceleration of the block can be calculated using the formula:

a = F / (M * g)

where a is the acceleration, F is the force applied, M is the mass of the block, and g is the acceleration due to gravity.

Substituting the given values, we get:

a = 65.0 N / (5.00 kg * 9.8 m/s²) = 1.33 m/s²

Therefore, the magnitude of the acceleration of the block is 1.33 m/s².

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