212k views
5 votes
Two pools are being filled with water. To start, the first pool had 992 liters of water and the second pool was empty. Water is being added to the first pool at a rate of 16 liters per minute Water is being added to the second pool at a rate of 48 liters per minute. (a) For each pool, write an expression for the amount of water in the pool after x minutes. Write an equation to show when the two pools would have the same amount of water.

User Favolas
by
7.4k points

1 Answer

0 votes

Final answer:

The first pool's water volume after x minutes is calculated by V1 = 992 + 16x, and the second pool's by V2 = 48x. Setting these expressions equal and solving for x gives us 31 minutes as the time it would take for both pools to have the same amount of water.

Step-by-step explanation:

The student has asked two questions related to rates of water flow and pool volume. First, we need to write expressions for the two pools being filled and then set up an equation to find when they would have the same amount of water.

Expression for Pool Volumes

First Pool: It starts with 992 liters and water is added at a rate of 16 liters per minute. So, after x minutes, the amount of water in the first pool (V1) would be:

V1 = 992 + 16x

Second Pool: It starts empty and water is added at a rate of 48 liters per minute. So, after x minutes, the amount of water in the second pool (V2) would be:

V2 = 48x

Equation for Equal Water Volumes

To find when both pools have the same amount of water, we set the two expressions equal to each other:

992 + 16x = 48x

Simplifying the equation:

992 = 48x - 16x

992 = 32x

x = 992 / 32

x = 31

Thus, it will take 31 minutes for both pools to have the same amount of water.

User SimenB
by
8.0k points