Question

Your friend David asks you to play the following number game:

1. Pick a number
2. Add 10
3. Multiply by 4
4. Subtract 7
5. Add the original number The number you end the game with is 93
Write an equation that could be used to solve for the number, n, you started with. 4(n+10)-7+n=93

Answer 1

The equation to find the original number n in David's number game is 4(n + 10) - 7 + n = 93. After solving the equation, the original number is found to be 12.

Step-by-step explanation:

To solve for the number (n) you started with in David's number game, you must set up an equation based on the steps provided:

1. 
   
3. Pick a number (n).
4. 
   
6. Add 10 to n (n + 10).
7. 
   
9. Multiply the result by 4 (4 × (n + 10)).
10. 
    
12. Subtract 7 from the result (4 × (n + 10) - 7).
13. 
    
15. Add the original number n (4 × (n + 10) - 7 + n).

The final result after these steps is 93, so the equation based on the game is:

4(n + 10) - 7 + n = 93

To find the original number n, we'll solve this equation:
4n + 40 - 7 + n = 93
Combine like terms:
5n + 33 = 93
Subtract 33 from both sides:
5n = 60
Divide both sides by 5:
n = 12

The number you started with is 12.