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According to a recent poll, 58% of registered voters support measure r and 47% support measure s. 39% support both. if a randomly selected voter is surveyed find the probability that that voter

a. supports neither measure______

1 Answer

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Final answer:

To find the probability that a randomly selected voter supports neither Measure R nor Measure S, we subtract the total percentage of voters that support either measure (66%) from 100%, resulting in 34%.

Step-by-step explanation:

To find the probability that a randomly selected voter supports neither Measure R nor Measure S, we can use the principle of inclusion-exclusion. According to the given poll percentages, 58% support Measure R, 47% support Measure S, and 39% support both. The principle of inclusion-exclusion tells us to add the probabilities of each group separately and then subtract the intersection once (since we've counted it twice).

The calculation would be as follows:

  • P(R) = 58%
  • P(S) = 47%
  • P(R and S) = 39%
  • P(R or S) = P(R) + P(S) - P(R and S)
  • P(R or S) = 58% + 47% - 39% = 66%

The probability that a voter supports either measure is 66%. To find the probability of a voter supporting neither, we subtract from 100%:

  • P(neither R nor S) = 100% - P(R or S)
  • P(neither R nor S) = 100% - 66% = 34%

Therefore, the probability that a randomly selected voter supports neither measure is 34%.

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