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The mouse genome consists of 2,700 Mb. A genomic library is constructed using BAC vectors and overlapping fragments of the mouse genome. The average size of the mouse DNA inserts is 200 kb. How many clones would make up one genomic equivalent?

a)13,500
b)270,000
c)270
d)135

User Feng
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Final answer:

To create a genomic library for the mouse genome using BAC vectors with 200 kb inserts, 13,500 clones are needed to represent one genomic equivalent, which ensures that every part of the genome is covered.

Step-by-step explanation:

Creating a genomic library involves cloning fragments of an organism's DNA into a vector. Given that the mouse genome is 2,700 Mb (or 2,700,000 kb) and the BAC vectors are designed to carry, on average, 200 kb per insert, we calculate the number of clones needed for one genomic equivalent by dividing the total genome size by the size of the inserts. Therefore, it's simply 2,700,000 kb / 200 kb per clone, which equals 13,500 clones.

This calculation assumes that there is no overlap between the inserts and that every part of the genome is represented once. In practice, some redundancy is necessary to ensure full coverage of the genome, but for the purpose of this calculation, we're aiming for a single genomic equivalent.

The final answer to how many clones would make up one genomic equivalent of the mouse genome when using BAC vectors with 200 kb inserts is 13,500 clones, corresponding to option (a).

User Sharese
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