Question

Calculate the energy, in electron volts, of a photon whose frequency is
(a) 6.20 x 10² THz,

Answer 1

The energy of a photon with a frequency of 6.20 x 10^14 Hz is calculated using the formula E = hf, where E is the energy, h is Planck's constant, and f is the frequency. The result is approximately 2.565 electron volts after converting from joules to electron volts.

Step-by-step explanation:

The student is asking to calculate the energy of a photon whose frequency is 6.20 x 1014 Hz. To find the energy of a photon, we use the formula E = hf, where E is the energy in joules, h is Planck's constant (6.626 x 10-34 J*s), and f is the frequency in hertz. However, the student is interested in the energy in electron volts (eV), so after calculating the energy in joules, we will need to convert it using the fact that 1 eV equals 1.602 x 10-19 joules.

To calculate the energy in electron volts for the given frequency:

1. Calculate the energy in joules: E = (6.626 x 10-34 J*s) x (6.20 x 1014 Hz) = 4.108 x 10-19 J.
2. Convert the energy to electron volts: E (in eV) = 4.108 x 10-19 J / (1.602 x 10-19 joules/eV) ≈ 2.565 eV.

Therefore, the energy of a photon with a frequency of 6.20 x 1014 Hz is approximately 2.565 electron volts.