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15 votes
If you have a 1234 gram sample of C4H7NO4, how many gams of Carbon would

be present?

User VBlades
by
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1 Answer

6 votes

Answer: 445.4 grams of carbon would be present.

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance contains avogadro's number
6.023* 10^(23) of particles and weighs equal to its molecular mass.

To calculate the moles, we use the equation:


\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=(1234g)/(133g/mol)=9.28moles

As 1 mole of
C_4H_7NO_4 gives = 4 moles of carbon

Thus 9.28 moles of
C_4H_7NO_4 gives =
(4)/(1)* 9.28=37.1 moles of carbon

Mass of carbon =
moles* {\text {Molar mass}}=37.1moles* 12g/mol=445.4g

Thus there are 445.4 grams of carbon would be present.

User Dmytroy
by
8.8k points
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