Question

If you have a 1234 gram sample of C4H7NO4, how many gams of Carbon would

be present?

Answer 1

Answer: 445.4 grams of carbon would be present.

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance contains avogadro's number
`6.023* 10^(23)` of particles and weighs equal to its molecular mass.

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=(1234g)/(133g/mol)=9.28moles`

As 1 mole of
`C_4H_7NO_4` gives = 4 moles of carbon

Thus 9.28 moles of
`C_4H_7NO_4` gives =
`(4)/(1)* 9.28=37.1` moles of carbon

Mass of carbon =
`moles* {\text {Molar mass}}=37.1moles* 12g/mol=445.4g`

Thus there are 445.4 grams of carbon would be present.