Loan borrowed = $12,000
Percentage of interest on the loan per annum = 14%
We know that :
![\color{hotpink}\tt \: Simple \: interest = \color{plum}(principal * rate * time)/(100)](https://img.qammunity.org/2022/formulas/computers-and-technology/high-school/nat4cdt3faaextb4px2lh2rqcjppkhf31g.png)
In this case :
- principal = $12000
- rate = 14%
- time = 1 year
Simple interest at the end of the first year :
![= \tt (12000 * 14 * 1)/(100)](https://img.qammunity.org/2022/formulas/computers-and-technology/high-school/f5fp6fr2lv7snpwn8jw8y4ibmccuo6pc7n.png)
![= \tt (168000)/(100)](https://img.qammunity.org/2022/formulas/computers-and-technology/high-school/unn34lzk059c9pp4yo5p91ghxouh9eowyj.png)
![\color{plum}\tt = \$1680](https://img.qammunity.org/2022/formulas/computers-and-technology/high-school/k49s8cqbwyprc69ejphhvdvthsh1du5gq6.png)
Thus, interest = $1680
Therefore, total interest on the loan at the end of one year = $1680