Question

Paki answer na po thank you in advance​

Answer 1

`40 = k(10) / {4}^(2)`

`(40)/(10) = \frac{k(10) / {4}^(2) }{10}`

`4 = k / {4}^(2)`

`4 * {4}^(2) = k / {4}^(2) * {4}^(2)`

`64 = k`

//

`216 = k {(3)}^(2)(12)`

`\frac{216}{ {(3)}^(2)(12) } = \frac{k {(3)}^(2)(12) }{ {(3)}^(2)(12)}`

`2 = k`

//

`72 = k {(2}^(2)) {(3}^(2))`

`\frac{72}{ {(2}^(2)) {(3}^(2)) } = \frac{k {(2}^(2)) {(3}^(2) ) }{ {(2}^(2)) {(3}^(2)) }`

`2 = k`

//

`90 = k(15)(2)`

`(90)/((15)(2)) = (k(15)(2))/((15)(2))`

`3 = k`

//

`10 = k(2)`

`(10)/((2)) = (k(2))/((2))`

`5 = k`

//

Okay, it's pretty much the same process. That's all I can do. good luck!