Question

The efficiency of a Carnot engine is 50%, and the temperature of the sink is 500 K. If the temperature of the source is kept constant and its efficiency is raised to 60%, then the required temperature of the sink will be:________

Answer 1

To determine the required temperature of the sink when the efficiency of a Carnot engine is raised from 50% to 60%, we need to use the Carnot efficiency formula.

Step-by-step explanation:

To determine the required temperature of the sink when the efficiency of a Carnot engine is raised from 50% to 60%, we need to use the Carnot efficiency formula:

Carnot efficiency = 1 - (Tc/Th)

Where Tc is the temperature of the sink and Th is the temperature of the source.

Given that the initial efficiency is 50%, we can substitute the values to find Tc: 0.5 = 1 - (Tc/Th)

For the new efficiency of 60%, we substitute the values again: 0.6 = 1 - (Tc/Th)

Since Th is constant, we can set the two equations equal to each other and solve for Tc: 0.5 = 1 - (Tc/Th) = 0.6 = 1 - (Tc/Th)

By solving these equations simultaneously, we can find the required temperature of the sink.