Final answer:
The density of US nickels is approximately 8.57g/cm³
Step-by-step explanation:
The density (ρ) of an object is given by the formula:
ρ = m/v
where m is the mass and V is the volume. The volume of a cylinder (which approximates the shape of a nickel) is given by: V=πr²h
Given the mass m=5.00g and thickness ℎ=1.95mm, we need to convert the thickness to meters (1.95=0.00195m).
The radius (r) can be obtained by dividing the diameter of a nickel (assuming it is a perfect cylinder) by 2. The diameter of a nickel is 21.21 mm, so r=10.605mm=0.010605m.
Now, substitute these values into the formulas:
V = πr²h
V = π (0.010605m)² × 0.00195m
ρ = 5.00g/v
After calculating these expressions, we find the density of US nickels to be approximately 8.57g/cm³. This density value provides insight into the compactness of the material used in the production of US nickels and is crucial for understanding their physical properties.