Final answer:
To calculate the partial products of 17 times 28, you multiply the ones digit of the second number by the first number to get 136, and the tens digit of the second number by the first number to get 340. Adding these together yields the final product of 476, which is present in option A, although individual partial products are not listed correctly. None of the Option is correct.
Step-by-step explanation:
The student asked for the partial products of the multiplication 17 times 28. To find the partial products, we multiply each digit of one number by each digit of the other, taking the place value into consideration.
Multiply the ones place of the second number by the first number: 8 (ones) * 17 = 136, and because it's in the ones place, it remains 136.
Multiply the tens place of the second number by the first number: 2 (tens) * 17 = 34, and because it's in the tens place, we must consider the '0' which will make it 340.
Add the two partial products: 136 (from step 1) + 340 (from step 2) = 476.
Therefore, the correct partial products are 136 and 340, which add up to 476. The options given in the question do not list the individual partial products correctly, but the total product of 476 matches option A. No other option gives a correct sequence of partial products for the given multiplication task.