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Given that

f(x) = 1/(3x)
g(x) = 1/(3x - c), find some integer c such that:

A) c = 1
B) c = 2
C) c = 3
D) c = 4

1 Answer

1 vote

Final answer:

To find an integer value for c such that g(x) = 1/(3x - c) is different from f(x) = 1/(3x), c should not be 3. Therefore, the possible correct answers are c = 1, c = 2, and c = 4.

Step-by-step explanation:

The student's question revolves around finding an integer value for c such that the function g(x) = 1/(3x - c) is defined. Given the options A) c = 1, B) c = 2, C) c = 3, and D) c = 4, we want to identify a value of c such that g(x) is a valid function and is different from the function f(x) = 1/(3x).

To ensure that g(x) is different from f(x), we need to choose a c value that changes the denominator in a way that it does not simplify to 3x. If c were 3, then the denominator of g(x) would become 3x - 3 = 3(x - 1), which could simplify to a similar form as f(x) after factoring out the 3. Therefore, to keep the functions distinct, c should not be 3, leaving us with the options A) c = 1, B) c = 2, and D) c = 4 as potential correct answers.

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