Question

find all zeros of9x³-24x²-41x-28 . enter the zeros separated by commas. enter exact value, not decimal approximations.

Answer 1

The zeros of the polynomial 9x³ - 24x² - 41x - 28 are -4/3, 1, -7/3.

Step-by-step explanation:

To find the zeros of the polynomial 9x³ - 24x² - 41x - 28, we can use the Rational Root Theorem and synthetic division.

The Rational Root Theorem states that if a polynomial has a rational root of the form p/q, where p is a factor of the constant term (in this case 28) and q is a factor of the leading coefficient (in this case 9), then p/q is a possible rational root of the polynomial.

By trying out the different factors of 28/9, you can find that the zeros of the polynomial are:

x = -4/3, x = 1, x = -7/3