58.8k views
4 votes
Use the factor theorem to determine whether v⁵ is a factor of v⁴ - 16v³ + 8v² - 725.

a) No
b) Yes

1 Answer

5 votes

Final answer:

Using the Factor Theorem, we find that vµ is not a factor of the polynomial because substituting v = 0 into the polynomial results in -725, not 0.

Step-by-step explanation:

To determine whether vµ is a factor of v⁴ - 16v³ + 8v² - 725, we can use the Factor Theorem. The Factor Theorem states that if f(x) is a polynomial and f(a) = 0, then (x - a) is a factor of f(x). For to be a factor of the polynomial, the remainder when the polynomial is divided by v must be zero.

This would imply that substituting v = 0 into the polynomial must result in a value of 0. Doing so, we get 0⁴ - 16·(0³) + 8·(0²) - 725 which simplifies to -725. Since -725 is not equal to 0, vµ is not a factor of the polynomial. Hence, the correct answer is: (a) No.

The factor theorem states that if a polynomial f(x) is divisible by (x - a), then f(a) = 0. In this case, we need to determine whether v^5 is a factor of v^4 - 16v^3 + 8v^2 - 725. To do this, we can substitute v = 0 into the polynomial and check if it equals 0:

f(0) = (0)^4 - 16(0)^3 + 8(0)^2 - 725 = -725

Since f(0) = -725 and it's not equal to 0, we can conclude that v^5 is not a factor of the polynomial. Therefore, the answer is a) No.

User Paul John
by
8.6k points

Related questions

asked Jun 1, 2024 159k views
Skyhan asked Jun 1, 2024
by Skyhan
7.4k points
1 answer
0 votes
159k views
1 answer
5 votes
204k views