Question

What are the x and y-intercepts of the line described by the equation 4x−8y=40?

a) x-intercept = (10, 0), y-intercept = (0, -5)
b) x-intercept = (0, 5), y-intercept = (10, 0)
c) x-intercept = (10, 0), y-intercept = (0, -10)
d) x-intercept = (0, -10), y-intercept = (10, 0)

Answer 1

The x-intercept of the line is (10, 0) and the y-intercept is (0, -5).

Step-by-step explanation:

The x-intercept is the point where the line crosses the x-axis, and the y-intercept is the point where the line crosses the y-axis. To find the x-intercept, we set y equal to 0 and solve for x. Plugging in y=0 in the equation 4x−8y=40, we get 4x - 8(0) = 40, which simplifies to 4x = 40. Dividing both sides by 4, we find that x = 10. So, the x-intercept is (10, 0).

To find the x-intercept of the line 4x−8y=40, we set y to 0 and solve for x:

4x−0=40 → x=10. So, the x-intercept is (10, 0).

To find the y-intercept, we set x equal to 0 and solve for y. Plugging in x=0 in the equation 4x−8y=40, we get 4(0) - 8y = 40, which simplifies to -8y = 40. Dividing both sides by -8, we find that y = -5. So, the y-intercept is (0, -5).

To find the y-intercept, we set x to 0 and solve for y:

0−8y=40 → y=-5. Thus, the y-intercept is (0, -5).

Therefore, the correct answer is a) x-intercept = (10, 0), y-intercept = (0, -5).