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Please help me!!!!!!!

Please help me!!!!!!!-example-1
User Misterte
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The graph of y = -x + 1 is a straight line with a slope of -1 and a y-intercept at (0, 1). Key points include the y-intercept (0, 1), (1, 0), and another point (2, -1).

To graph the equation y + 2 = -(x - 3), let's first rewrite it in slope-intercept form (y = mx + b):

y + 2 = -(x - 3)

Distribute the negative sign:

y + 2 = -x + 3

Subtract 2 from both sides:

y = -x + 1

Now, the equation is in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.

**Slope:** The coefficient of x is -1, so the slope (m) is -1.

**Y-Intercept:** The y-intercept (b) is 1.

Now, let's plot the graph using the slope and y-intercept.

**Graph:**

1. Plot the y-intercept at the point (0, 1).

2. Use the slope to find another point. The slope is -1, so from the y-intercept, move down 1 unit and to the right 1 unit to get another point (1, 0).

3. Choose another point. For example, let x = 2. Substitute into the equation to find y:

y = -x + 1

y = -2 + 1

y = -1

So, another point is (2, -1).

Now, plot these points and draw the line. The graph should show a straight line with a slope of -1 and a y-intercept at (0, 1).

Please help me!!!!!!!-example-1
User Tomjosef
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