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At 900°C, what is the equilibrium constant (Kp) for the reaction

CaCO₃(s)?
A) 1.09
B) 0.90
C) 2.00
D) 1.00

User Maccullt
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1 Answer

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Final answer:

Without the specific data for 900°C, such as CO₂ concentration at equilibrium, we cannot accurately provide the Kp for the decomposition of CaCO₃ at that temperature.

Step-by-step explanation:

The equilibrium constant for the decomposition of CaCO₃(s) into CaO(s) and CO₂(g) can be represented as Kp = [CO₂]. At 800°C, the concentration of CO₂ in equilibrium is given as 2.5 × 10⁻³ M, and so the equilibrium constant K at 800°C is also 2.5 × 10⁻³. Given that the question asks for the equilibrium constant at 900°C instead, but does not provide the necessary data for that specific temperature, we cannot accurately determine the equilibrium constant at 900°C without additional data, like CO₂ equilibrium concentration at 900°C or a Van't Hoff plot.

User Jim Jin
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