Assume that a, b, and c have been declared and initialized with int values. The expression !(a > b || b <= c) is equivalent to which of the following: a) -a > b &&a…

Question

Assume that a, b, and c have been declared and initialized with int values. The expression !(a > b || b <= c) is equivalent to which of the following:

a) -a > b && b <= c
b) -a < b || b >= c
c) -a <= b && b > c
d) -a <= b || b > c

Answer 1

The equivalent expression for !(a > b || b <= c) is a <= b && b > c, after applying De Morgan's laws.

The expression !(a > b || b <= c) uses logical NOT (!) and OR (||) operators. To find an equivalent expression without the negation, we need to apply De Morgan's laws. De Morgan's laws state that the negation of a disjunction (a || b) is equivalent to the conjunction of the negations (i.e., !a && !b). Therefore, the negation of a > b || b <= c is a <= b && b > c.

So the expression !(a > b || b <= c) is equivalent to a <= b && b > c. This makes the correct answer to the original question (c) -a <= b && b > c assuming that the minus sign in front of 'a' in the options was a typographical error and not meant to suggest negating the value of 'a'.