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The curved rod lies in the x-y plane and has a radius of 3 m.

A) Angular velocity,
B) Centripetal force,
C) Torque,
D) Centrifugal acceleration

1 Answer

4 votes

Final answer:

A) Angular velocity is the rate at which an object rotates, B) Centripetal force keeps an object moving in a circular path, C) Torque measures rotational force, D) Centrifugal acceleration is not a real force

Step-by-step explanation:

A) Angular velocity is the rate at which an object rotates around an axis. In this case, the rod is rotating in the x-y plane, so its angular velocity would be given by the formula ω = Δθ/Δt, where ω is the angular velocity, Δθ is the change in angle, and Δt is the change in time. To find the instantaneous angular velocity at t = 5s, you would need more information.

B) Centripetal force is the force that keeps an object moving in a circular path. For an object with mass m moving in a circular path with radius r and angular velocity ω, the centripetal force is given by Fc = mω^2r. In this case, the centripetal force will depend on the mass of the rod and the radius of its circular path.

C) Torque is the measure of how much a force acting on an object causes it to rotate. In this case, the torque would depend on the force acting on the rod and its moment arm, which is the perpendicular distance from the axis to the line of action of the force.

D) Centrifugal acceleration is the apparent outward force that appears to act on an object moving in a curved path. However, centrifugal acceleration is not actually a real force, but is rather the result of inertia resisting changes in motion. Therefore, it cannot be directly calculated.

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