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When 25 ml of liquid is poured into a 112 g beaker, the liquid container mass is 134 g. What is the liquid's specific gravity?

a) 0.89
b) 1.12
c) 1.50
d) 1.79

User Ravidl
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1 Answer

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Final answer:

The specific gravity of the liquid is calculated by finding its density and dividing it by the density of water. After determining the mass of the liquid and using its volume, we find that the closest answer to the calculated specific gravity of 0.88 is option (a) 0.89.

Step-by-step explanation:

To calculate the specific gravity of an unknown liquid, we can use the formula:

Specific Gravity (SG) = \( \frac{Density of Substance}{Density of Water} \)

The density of water at room temperature is 1.00 g/mL, which is the reference substance for specific gravity.

First, we need to determine the mass of the liquid alone:

  • Mass of beaker + liquid = 134 g
  • Mass of beaker = 112 g
  • Mass of liquid = 134 g - 112 g = 22 g

We were given the volume of the liquid as 25 mL. Now, we can calculate the density:

Density of Liquid = Mass/Volume = 22 g / 25 mL = 0.88 g/mL

Finally, calculate the specific gravity:

Specific Gravity = Density of Liquid/Density of Water = 0.88 g/mL / 1.00 g/mL = 0.88

Comparing this with the given options, the correct answer is (a) 0.89, as this is the closest to our calculated value. Please note, a slight discrepancy can arise due to rounding.

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