Final answer:
To find the moles of ammonium ion in 6.955 g of ammonium carbonate, calculate the molar mass of the compound, determine the moles of the compound, and then multiply by 2 because of the two ammonium ions present per formula unit. The resulting value is approximately 0.1448 mol, with the closest provided answer being 0.1 mol.
Step-by-step explanation:
The question is asking to calculate the number of moles of ammonium ion in 6.955 g of ammonium carbonate. To find this, we first need to find the molar mass of ammonium carbonate (NH4)2CO3. Ammonium carbonate consists of 2 ammonium ions (NH4+) and 1 carbonate ion (CO32-). The molar mass of ammonium carbonate can be calculated by (2 x 14.01 for nitrogen) + (8 x 1.008 for hydrogen from the 2 ammonium ions) + (12.01 for carbon) + (3 x 16.00 for oxygen), which equals 96.09 g/mol.
Now, to find the number of moles of ammonium carbonate in 6.955 g, we use the formula:
moles = mass (g) / molar mass (g/mol)
moles of ammonium carbonate = 6.955 g / 96.09 g/mol
After the calculation, the moles of ammonium carbonate is found to be approximately 0.0724 mol. Since there are 2 moles of ammonium ion for every mole of ammonium carbonate, we multiply 0.0724 mol by 2 to get the moles of ammonium ion:
0.1448 mol of ammonium ion.
This is not an option provided in the original multiple-choice question, suggesting a possible error in the question or the answer options provided. However, the closest answer from the provided options is 0.1 mol (option a).