Question

What is the probability that a value picked at random from the standard normal distribution will be between -1.96 and 1.96?

Answer 1

P( -1.96 ≤ Z≤ 1.96) = 0.95

Explanation:

Explanation:-

Given that the z -scores -1.96 and 1.96

we have to find P( -1.96 ≤ Z≤ 1.96)

P( -1.96 ≤ Z≤ 1.96) = |A(1.96)+A(-1.96)|

= |A(1.96)+A(-1.96| (∵A(-Z) = A(Z))

= 0.4750+0.4750

= 2×0.4750

= 0.95

The probability lies between -1.96 to 1.96

P( -1.96 ≤ Z≤ 1.96) = 0.95