Question

A gas at 127 celsius and 10.0 L expands to 20.0 L. What is the new

temperature in kelvin? (You must convert to Kelvin before calculating
this problem

Answer 1

T₂ = 800 K

Step-by-step explanation:

Given that,

Initial temperature of the gas, T₁ = 127°C = 400 K

Initial volume, V₁ = 10 L

Final volume, V₂ = 20 L

We need to find the new temperature.

The volume of a gas is directly proportional to its Kelvin temperature.

Let T₂ is the new temperature. So,

`(V_1)/(T_1)=(V_2)/(T_2)\\\\T_2=(V_2T_1)/(V_1)\\\\T_2=(20* 400)/(10)\\\\T_2=800\ K`

So, the new temperature of the gas is 800 K.