Final answer:
The electric field does 2.64 x 10^-17 joules of work to move a proton from a point with a potential of 115 V to a point with a potential of -50 V.
Step-by-step explanation:
The work done by an electric field in moving a charge, such as a proton, is given by the equation W = -qΔV, where W is the work, q is the charge of the proton, and ΔV is the change in electric potential. In this case, to move a proton from a point with an initial potential of 115 V to a final potential of -50 V, you would calculate the work done using the electric potential difference (ΔV = V_final - V_initial) and the charge of a proton (approximately 1.602 x 10^-19 C).
Therefore, the work done by the electric field is calculated as follows:
ΔV = (-50 V) - (115 V) = -165 V
W = -(1.602 x 10^-19 C) x (-165 V) = 2.64 x 10^-17 J
The electric field does 2.64 x 10^-17 joules of work in moving the proton.