Question

A line is parallel to y = 3x + 5 and

intersects the point (-2, 6). What is
the equation of this parallel line?
Start by entering this into point-slope form.
y- [?] = [](x
](x-[]).

Answer 1

Im not like 100% sure but i think you answer is

y-6=3[x-(-2)]

y=6+3x+6

y=3x+12

And i believe that this is parallel to y

Answer 2

• y = 3x + 12

Explanation:

Parallel lines have same slope

Given line

• y = 3x + 5

The line that passes through (-2, 6) and with the slope of 3 is:

• y - y₁ = m(x - x₁)
• y - 6 = 3(x - (-2))
• y - 6 = 3(x + 2)

Convert the equation into slope-intercept form:

• y - 6 = 3x + 6
• y = 3x + 6 + 6
• y = 3x + 12