Final answer:
The force experienced by the proton due to the electric field created by the charged plane is -2.89 x 10^-17 N.
Step-by-step explanation:
To calculate the force experienced by the proton due to the electric field created by the charged plane, we can use the following formula:
F = q * E
Where F is the force, q is the charge of the proton, and E is the electric field. The charge of the proton is +1.602 x 10^-19 C and the electric field can be calculated using the surface charge density:
E = sigma / epsilon_0
Where sigma is the surface charge density (-1.60 x 10^-6 C/m^2) and epsilon_0 is the permittivity of free space (8.85 x 10^-12 C^2/N*m^2).
Substituting the values, we have:
E = (-1.60 x 10^-6 C/m^2) / (8.85 x 10^-12 C^2/N*m^2)
E = -180.79 N/C
Now, we can calculate the force:
F = (1.602 x 10^-19 C) * (-180.79 N/C)
F = -2.89 x 10^-17 N
Therefore, the force experienced by the proton is -2.89 x 10^-17 N.