Question

Where do you need to put a target that is 1.45 m above the ground in order to hit it if you aim 30° above the horizontal while pulling the bow in the same way?

Answer 1

To hit a target that is 1.45 m above the ground when aiming 30° above the horizontal, you need to place the target at a certain horizontal distance that can be calculated using the concepts of projectile motion.

Step-by-step explanation:

To hit a target that is 1.45 m above the ground when aiming 30° above the horizontal, you need to place the target at a certain horizontal distance from the starting point. This can be calculated using the concepts of projectile motion.

The horizontal distance can be found using the equation:

d = \frac{{v^2 \sin(2\theta)}}{{g}}

where:

• d is the horizontal distance
• v is the initial velocity of the arrow
• θ is the angle of projection
• g is the acceleration due to gravity (approximately 9.8 m/s²)

By substituting the given values, you can find the horizontal distance at which you need to place the target in order to hit it.