Question

Two protons are 1 meter apart. Determine the Fg and Fe. How do the forces of Gravitation and Coulomb’s Law impact the system? Does the force cause the protons to attract or repulse? Is the force always that way or just due to the system being 2 protons? Which Force is larger? By how much?

Answer 1

Step-by-step explanation:

Given:

q₁ = q₂ = q = +1.6·10⁻¹⁹ C

m₁ = m₂ = m = 1.67·10⁻²⁷ kg

r = 1 m

k =

G = 6.67·10⁻¹¹ N·m² / kg²

k = 9·10⁹ N·m² / C²

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Fg - ?

Fe - ?

Gravitational force of attraction of protons:

Fg = G·m₁·m₂ / r² = G·m² / r²

Coulomb repulsive force of protons:

Fe = k·q₁·q₂ / r² = k·q² / r²

The Coulomb force of repulsion of protons is greater than the force of gravitational attraction of protons:

Fe / Fg = k·q² / (G·m²) = (k/G)· (q/m)²

Fe / Fg = (9·10⁹ /6.67·10⁻¹¹)· (1.6·10⁻¹⁹/1.67·10⁻²⁷ )² ≈ 1,2·10³⁶ times more

Answer 2

fe

Step-by-step explanation:

so if the Impact of the system is 2 than it appositive will be fe