Question

3

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Solve (y+4) 2 = 2 where y is a real number.
Simplify your answer as much as possible.

Answer 1

Explanation:

Did you mean (y+4)^2 = 2? " ^ " denotes exponentiation.

Expanding (y+4)^2 = 2, we get y^2 + 8y + 16 = 2, or

y^2 + 8y + 14 = 0

Let's apply the quadratic formula. First, find the discriminant, b^2 - 4ac:

8^2 - 4(1)(14) = 64 - 56 = 8 (which is the square of 2√2).

Because the discriminant is positive, there are two real, unequal roots (solutions). They are:

-8 ± √8

x = -------------- = -4 ± √2

2

Answer 2

i believe the answer is y= -3