Question

reciprocating air compressor taken in 2m3/min air at 0.11MPa, 293K which it delivers at 1.5 Mpa, 384 K to an after cooler where the air where the air is cooled at constant pressure to 298 K. the power absorbed by the compressor is 4.15 kW. Calculate the heat transfer in (i) the compressor (ii) the cooler. State your assumptions.

Answer 1

To calculate the heat transfer in the compressor and cooler, we use the equation Q = mc(T2 - T1). Assumptions made are that the air can be treated as an ideal gas and there are no heat losses to the surroundings.

Step-by-step explanation:

To calculate the heat transfer in the compressor and cooler, we can use the equation:

Q = mc(T2 - T1)

Where Q is the heat transfer, m is the mass flow rate of air, c is the specific heat capacity of air, and T2 and T1 are the final and initial temperatures, respectively.

(i) In the compressor:

Given: V1 = 2 m³/min, P1 = 0.11 MPa, T1 = 293 K

Using the ideal gas law, we can calculate the density of air and convert the volume flow rate to mass flow rate.

(ii) In the cooler:

Given: P2 = 1.5 MPa, T3 = 298 K

Since the cooling process is at constant pressure, the heat transfer can be calculated directly using the equation provided.

Assumptions made: The air can be treated as an ideal gas, and there are no heat losses to the surroundings.