Answer:
2 × 10²⁴ atoms Co
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Chemistry
Atomic Structure
- Reading a Periodic Table
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Stoichiometry
- Using Dimensional Analysis
Step-by-step explanation:
Step 1: Define
4 mol Co (Cobalt)
Step 2: Identify Conversions
Avogadro's Number
Step 3: Convert
- Set up:
![\displaystyle 4 \ mol \ Co((6.022 \cdot 10^(23) \ atoms \ Co)/(1 \ mol \ Co))](https://img.qammunity.org/2022/formulas/chemistry/high-school/sq8okyxmnqfys1syhwqoinny2qajuk18ok.png)
- Multiply/Divide:
![\displaystyle 2.4088 \cdot 10^(24) \ atoms \ Co](https://img.qammunity.org/2022/formulas/chemistry/high-school/ummnyy8lq90nnb569aliblnctxtv2cwwli.png)
Step 4: Check
Follow sig fig rules and round. We are given 1 sig fig.
2.4088 × 10²⁴ atoms Co ≈ 2 × 10²⁴ atoms Co