53.6k views
4 votes
The standard enthalpy of formation of NH₄Cl(s) is -315.4 kj/mol. the equation that describes this fh° is:

User JoshuaJ
by
7.9k points

1 Answer

5 votes

Final answer:

The equation for the standard enthalpy of formation of NH4Cl(s) is N2(g) + 4 H2(g) + Cl2(g) → 2 NH4Cl(s), indicating an exothermic reaction where NH4Cl(s) is formed from its elements in their standard states.

Step-by-step explanation:

The equation that describes the standard enthalpy of formation (ΔHf°) of NH4Cl(s) is given by the formation of the substance from its elements in their standard states. The enthalpy of formation is the heat change that results when one mole of a compound is formed from its elements in their standard states.

For ammonium chloride (NH4Cl), the equation would be:
N2(g) + 4 H2(g) + Cl2(g) → 2 NH4Cl(s)

Since the enthalpy of formation is negative (-315.4 kJ/mol), it indicates that the reaction is exothermic, meaning excess energy is released as heat when NH4Cl(s) is formed.

User Dave Konopka
by
8.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.