Question

9 mol P4010 reacts with 51 mol H₂O according to the equation below: P4010 + 6H₂O → 4H3PO4 How many moles of H3PO4 form from 51 mol H₂O? [?] mol H3PO4

Answer 1

To find the moles of H3PO4 formed from 51 mol H2O, we use the stoichiometric ratio in the balanced equation. The answer is 34 mol H3PO4.

Step-by-step explanation:

To find the number of moles of H3PO4 formed from 51 mol H2O, we can use the stoichiometric ratio between H3PO4 and H2O in the balanced chemical equation: P4010 + 6H2O -> 4H3PO4. According to the equation, 1 mol of P4010 reacts with 6 mol of H2O to produce 4 mol of H3PO4.

This means that the stoichiometric ratio of H3PO4 to H2O is 4:6 or 2:3. Therefore, for every 3 mol of H2O, we will have 2 mol of H3PO4. So, if we have 51 mol of H2O, we can set up a proportion: (2 mol H3PO4 / 3 mol H2O) = (x mol H3PO4 / 51 mol H2O). Solving for x, we get x = (2/3) * 51 = 34 mol H3PO4. Therefore, 34 mol H3PO4 will form from 51 mol of H2O.