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A boy runs at 8m/s starting from rest for 2 sec, then he walks at a constant speed for 2sec and then slows down to 4m/sec in 2 sec and finally he walks with constant speed for 4 sec and come to rest in 2 sec.

Plot the v-t graph for the motion

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The boy traveled a total distance of 44 meters.

Let's analyze the motion of the boy in different intervals and plot the velocity-time (v-t) graph, find the acceleration in each interval, and calculate the total distance traveled.

a. Velocity-Time (v-t) Graph:

First 2 seconds (Running at 8 m/s from rest):

Initial velocity (u) = 0 m/s

Final velocity (v) = 8 m/s

Time (t) = 2 seconds

Next 2 seconds (Walking at constant speed):

Initial velocity (u) = 8 m/s (from the previous interval)

Final velocity (v) = 8 m/s (constant speed)

Time (t) = 2 seconds

Next 2 seconds (Slowing down to 4 m/s):

Initial velocity (u) = 8 m/s

Final velocity (v) = 4 m/s

Time (t) = 2 seconds

Next 4 seconds (Walking at constant speed):

Initial velocity (u) = 4 m/s (from the previous interval)

Final velocity (v) = 4 m/s (constant speed)

Time (t) = 4 seconds

Last 2 seconds (Coming to rest):

Initial velocity (u) = 4 m/s

Final velocity (v) = 0 m/s

Time (t) = 2 seconds

Now, let's plot the v-t graph based on this information.

b. Acceleration in Each Interval:

Acceleration (a) is given by the formula:

a= Δv/Δt

First 2 seconds:

a= 8m/s−0m/s/2s−0s​ = 8m/s/2s =4m/s^2

Next 2 seconds:

Acceleration is zero since the speed is constant.

Next 2 seconds:

a= 4m/s−8m/s/2s−0s= −4m/s/2s​ =−2m/s^2

Next 4 seconds:

Acceleration is zero since the speed is constant.

Last 2 seconds:

a= 0m/s−4m/s/ 2s−0s = −4m/s/2s =−2m/s^2

c. Total Distance Traveled:

To find the total distance traveled, we need to calculate the distance in each interval and sum them up.

First 2 seconds:

s_1 =ut+ 1/2 at^2 =0×2+ 1/2 ×4×(2^2 )=4m

Next 2 seconds:

s_2 =ut+ 1/2 at^2 =8×2+ 1/2 ×0×(2^2 )=16m

Next 2 seconds:

s_3 =ut+ 1/2 at^2 =8×2+ 1/2 ×(−2)×(2^2 )=12m

Next 4 seconds:

s_4 =ut+ 1/2 at^2 =4×4+ 1/2 ×0×(4^2 )=16m

Last 2 seconds:

s_5 =ut+ 1/2 at^2 =0×2+ 1/2 ×(−2)×(2^2 )=−4m

Total Distance:

Total Distance=s_1 +s_2​ +s_3 +s_4 +s_5​ =4+16+12+16−4=44m

So, the boy traveled a total distance of 44 meters.

Question

1.A boy runs at 8m/s starting from rest for 2 sec, then he walks at a constant speed for 2sec and then slows down to 4m/sec in 2 sec and finally he walks with constant speed for 4 sec and come to rest in 2 sec a. Plot the v-t graph for the motion b. Find the acceleration in each interval c. How far the boy traveled in the whole time

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