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F(x) = 4²⁻⁶ find the domain, range and minimum value of

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Final answer:

The function F(x) = 4²⁻⁶, interpreted as a constant function, has a domain of all real numbers, a range of the single value 16⁻⁶, and this value is also its minimum. If the function is written as F(x) = (4x)² - 6, then the domain remains all real numbers, the range is all real numbers greater than or equal to -6, and the minimum value is -6.

Step-by-step explanation:

The expression F(x) = 4²⁻⁶ is somewhat ambiguous and makes it challenging to identify the correct mathematical function. Assuming it represents a constant function where the exponentiation is considered as applying to the number '4' solely and any operation with 'x' is excluded, the function simplifies to F(x) = 16⁻⁶, which is a constant value.

The domain of this function is all real numbers since there are no restrictions on the value of 'x' for a constant function. The range is a single number, which is also the minimum value of the function, resulting from the constant expression 16⁻⁶.

However, if the function is meant to be F(x) = (4x)² ⁻ 6, implying a square with a subtraction, then the domain is still all real numbers, the range is all real numbers greater than or equal to -6, and the minimum value is -6. As portions of the examples provided seem to derive from unrelated mathematical problems, they cannot be used to directly answer the question about the function F(x).

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