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"z=`ls`

echo $z
What does this output?
a) The results of ls command. The output is saved into the 'z' variable.
b) The variable 'z' is not assigned any value
c) The contents of the directory '/tmp/A'
d) Error occurred in the command execution"

1 Answer

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Final answer:

The command outputs the results of the 'ls' command, as the output is saved to the variable 'z' and then displayed with 'echo'.

Step-by-step explanation:

The command z=`ls` echo $z is intended to execute the ls command, save its output into the variable z, and then echo the value of z. However, due to the lack of a semicolon or new line between the assignment and echo command, the shell will first assign the output of ls to the variable z and then immediately output it using echo. As a result, the answer to the question is a) The results of ls command. The output is saved into the 'z' variable.

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