Final answer:
Using the work-energy principle, we calculate the work done by the force on the golf ball and determine that the ball leaves the club with a velocity of 72.8 m/s, which is not listed among the given options.
Step-by-step explanation:
We will use the work-energy principle to solve this problem. The work done on the golf ball by the golf club is equal to the change in kinetic energy of the golf ball:
Work done (W) = Change in kinetic energy (ΔKE)
Given that the net force (F) is 6600 N and the distance (d) over which this force is applied is 0.010 m (converting from millimeters to meters), we calculate the work done (W) as:
W = F * d = 6600 N * 0.010 m = 66 J
The change in kinetic energy is also the final kinetic energy of the ball (KEf), since it starts from rest. So:
KEf = ½ m * v2
Where m is the mass of the golf ball (0.05 kg) and v is the final velocity. To find v, we can rearrange the equation:
v = sqrt ((2 * KEf) / m)
Substituting the values gives us:
v = sqrt ((2 * 66 J) / 0.05 kg) = 72.8 m/s
Therefore, the correct answer is not listed in the options, as the calculated final velocity is 72.8 m/s.