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The equation below describes one or more physical processes:

0=(½)(1.0x10-4 kg)(6.0 m/s)2+(2.0x10-7 C)V
Part A: Solve the equation for the unknown.
Part B: Write a problem statement for which the equation is a satisfactory solution.

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Final answer:

To solve the equation, isolate the unknown V by multiplying both terms by 2. A satisfactory problem statement could involve finding the voltage required to bring a charged particle to a stop.

Step-by-step explanation:

Part A: To solve the equation, we need to isolate the unknown. In this case, the unknown is V. We can start by multiplying both terms by 2 to eliminate the fraction:
1.0x10^-4 kg * (6.0 m/s)^2 + 2.0x10^-7 C * V = 0
2.0x10^-4 kg * 36 m^2/s^2 + 2.0x10^-7 C * V = 0
V = - (2.0x10^-4 kg * 36 m^2/s^2) / (2.0x10^-7 C)

Part B: A problem statement for which the equation is a satisfactory solution could be finding the voltage required to bring a charged particle with a mass of 1.0x10^-4 kg and an initial velocity of 6.0 m/s to a stop.

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